How do you determine dy/dx given #x+siny=y+1#?

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Answer 1 · 2016-08-30T15:04:58

#dy/dx = 1/(1 - cosy)#

#d/dx(x + siny) = d/dx(y + 1)#

#d/dx(x) + d/dx(siny) = d/dx(y) + d/dx(1)#

#1 + cosy(dy/dx) = 1(dy/dx) + 0#

#1 = 1(dy/dx) - cosy(dy/dx)#

#1 = dy/dx(1 - cosy)#

#dy/dx = 1/(1 - cosy)#

Hopefully this helps!