How do you determine the amplitude of $y = 5 sin x$ $y= 5 sin x$ and $y = 3 cos x$ $y= 3 cos x$ ?

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Answer 1 · 2015-04-25T11:52:37

Both $sin (x) and cos (x)$ $sin(x) " and " cos(x)$ have a Range of
$[- 1, + 1]$ $[-1,+1]$

$y = 5 sin (x)$ $y=5sin(x)$
maps the points of $sin (x)$ $sin(x)$ into a stretched Range of
$[- 5, + 5]$ $[-5,+5]$
and thus an amplitude of $5$ $5$ .

Similarly
$y = 3 cos (x)$ $y=3cos(x)$
has an amplitude of $3$ $3$
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How do you determine the amplitude of y=5sinxy= 5 sin x and y=3cosxy= 3 cos x?