# How do you determine the amplitude, period, and phase shift for y = 4 sin {[2x - 2(pi)] / 3}?

$y = 4 \sin \left(\frac{2 x}{3} - \frac{2 \pi}{3}\right)$
Period: $3 \pi$
Phase shift: $\frac{- 2 \pi}{3}$