# How do you determine the area to the left of #g(y)=3-y^2# and to the right of #x=-1#?

##### 1 Answer

Determine the area to the left of

Turn your thinking

This is the dual problem of the problem: Find the area under

in terms of

in terms of

You don't need to change the problem if you can change your thinking. Usually (initially) we found the area between two functions ox

This time we'll do:

Limits of integration are the values of

So now we know to evaluate: