# How do you determine the intervals for which the function is increasing or decreasing given #f(x)=(2absx-3)^2+1#?

##### 1 Answer

Feb 14, 2017

#### Explanation:

This is the combined equation to the truncated parabolas

The vertices of these parabolas are at

The parabolas meet at (0, 10). This is the truncation point at which

one parabola changes to the other.

So,

graph{((x-3/2)^2-1/4(y-1))((x+3/2)^2-1/4(y-1))=0 [-10, 10, 0, 10]}