How do you determine the period and amplitude of the graph y = sin(x/2)?
1 Answer
Jan 15, 2017
#"period " =4pi," amplitude " =1#
Explanation:
The standard form of the
#color(blue)"sine function"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#
#"where amplitude " =|a|," period " =(2pi)/b#
#"phase shift " =-c/b" and vertical shift " =d#
#"here " a=1,b=1/2,c=0,d=0#
#rArr"period " =(2pi)/(1/2)=4pi" and amplitude " =|1|=1#
