# How do you determine the period and amplitude of the graph y = sin(x/2)?

##### 1 Answer
Jan 15, 2017

$\text{period " =4pi," amplitude } = 1$

#### Explanation:

The standard form of the $\textcolor{b l u e}{\text{sine function}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = a \sin \left(b x + c\right) + d} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

$\text{where amplitude " =|a|," period } = \frac{2 \pi}{b}$

$\text{phase shift " =-c/b" and vertical shift } = d$

$\text{here } a = 1 , b = \frac{1}{2} , c = 0 , d = 0$

$\Rightarrow \text{period " =(2pi)/(1/2)=4pi" and amplitude } = | 1 | = 1$