# How do you determine the quadrant in which (11pi)/8 lies?

$\frac{11 \pi}{8} = \frac{3 \pi}{8} + \pi$
On the unit circle, the arc (or angle) $\frac{3 \pi}{8}$ is located in Quadrant 1, therefor, the arc $\left(\frac{3 \pi}{8} + \pi\right)$ is located in Quadrant 3.