# How do you determine the quadrant in which -(11pi)/9 lies?

Feb 15, 2018

The negative means you go clockwise instead of counterclockwise to graph the angle. Then...

#### Explanation:

Then, since $\frac{11}{9}$ is a little more than one, it means the angle is a little more than $\setminus \pi$ (or 180 degrees). Therefore, when you graph an angle moving clockwise and go past $\setminus \pi$ radians, you will be in Quadrant II

Feb 22, 2018

#### Explanation:

$- \frac{11 \pi}{9} = - 1 \left(\frac{2 \pi}{9}\right) = - \pi - \left(\frac{2 \pi}{9}\right)$

$\implies 2 \pi - \pi - \left(\frac{2 \pi}{9}\right) = \frac{7 \pi}{9}$

Since $\frac{7 \pi}{9} > \frac{\pi}{2}$, it is in second quadrant.

Aliter : -(11pi)/9 = -((11pi)/9) * (360/2pi) = - 220^@#

$\implies 360 - 220 = {140}^{\circ} = {\left(90 + 50\right)}^{\circ}$

It’s in second quadrant, as ${140}^{\circ}$ is between ${90}^{\circ}$ and ${180}^{\circ}$