How do you determine whether (0,1) is a solution to #y > x - 1#? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables 1 Answer Alan P. Jul 16, 2015 #(x,y) = (0,1)# is a valid solution for #y > x - 1# Explanation: Substitute #0# for #x# and #1# for #y# and check if the inequality is valid. In this case #1 > 0 -1#, #color(white)("XXXX")#so #(x,y) = (0,1)# is a valid solution. Answer link Related questions How do you graph linear inequalities in two variables? How many solutions does a linear inequality in two variables have? How do you know if you need to shade above or below the line? What is the difference between graphing #x=1# on a coordinate plane and on a number line? How do you graph #y \le 4x+3#? How do you graph #3x-4y \ge 12#? How do you graph #y+5 \le -4x+10#? How do you graph the linear inequality #-2x - 5y<10#? How do you graph the inequality #–3x – 4y<=12#? How do you graph the region #3x-4y>= -12#? See all questions in Linear Inequalities in Two Variables Impact of this question 3379 views around the world You can reuse this answer Creative Commons License