How do you graph #y \le 4x+3#?

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Answer 1 · 2014-10-29T21:33:54

First, sketch the line #y=4x+3# (in a solid line since it is not a strict inequality), which looks like:

enter image source here

Choose any sample point that is NOT on the line. I use #(0,0)# to see if it satisfies the inequality:

#0 le 4(0)+3#.

Since #(0,0)# satisfies the inequality, we shade the side containing #(0,0)#, which looks like:

enter image source here

That is how you graph #y le 4x+3#.

I hope that this was helpful.