How do you graph $y \leq 4 x + 3$ $y \le 4x+3$ ?

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Answer 1 · 2014-10-29T21:33:54

First, sketch the line $y = 4 x + 3$ $y=4x+3$ (in a solid line since it is not a strict inequality), which looks like:

enter image source here

Choose any sample point that is NOT on the line. I use $(0, 0)$ $(0,0)$ to see if it satisfies the inequality:

$0 \leq 4 (0) + 3$ $0 le 4(0)+3$ .

Since $(0, 0)$ $(0,0)$ satisfies the inequality, we shade the side containing $(0, 0)$ $(0,0)$ , which looks like:

enter image source here

That is how you graph $y \leq 4 x + 3$ $y le 4x+3$ .

I hope that this was helpful.

How do you graph y \le 4x+3y≤4x+3y \le 4x+3?