How do you graph #y \le 4x+3#?

1 Answer
Oct 29, 2014

First, sketch the line #y=4x+3# (in a solid line since it is not a strict inequality), which looks like:

enter image source here

Choose any sample point that is NOT on the line. I use #(0,0)# to see if it satisfies the inequality:

#0 le 4(0)+3#.

Since #(0,0)# satisfies the inequality, we shade the side containing #(0,0)#, which looks like:

enter image source here

That is how you graph #y le 4x+3#.


I hope that this was helpful.