# How do you determine which is greater (8^2)^2 (<=>) (8^2)^3?

Mar 2, 2018

${\left({8}^{2}\right)}^{3}$

#### Explanation:

Let $x = {\left({8}^{2}\right)}^{2}$.

We have:

${\left({8}^{2}\right)}^{3}$

$= {\left({8}^{2}\right)}^{2} \cdot {8}^{2}$

$= x \cdot {8}^{2}$

$= 64 x$

Since $64 > 1$, we have $64 x > x$, or ${\left({8}^{2}\right)}^{3} > {\left({8}^{2}\right)}^{2}$.