How do you differentiate f(x)=1/(x-3)^2 using the chain rule?

Jun 7, 2018

$f ' \left(x\right) = - \frac{2}{x - 3} ^ 3$

Explanation:

Writing
$f \left(x\right) = {\left(x - 3\right)}^{- 2}$

then we get after

$\left({x}^{n}\right) ' = n {x}^{n - 1}$

$f ' \left(x\right) = - 2 {\left(x - 3\right)}^{- 3}$