Question

How do you differentiate `f(x)=3-7x^3+3x^7`?

Answer 1

Therefore, differentiating `f(x)=3-7x^3+3x^7.` w.r.t `x`, comes to be `-21x^2+21x^6.` (answer).

Explanation:

Let, `y=f(x)=3-7x^3+3x^7.`

`:.`Differentiating `y` w.r.t `x` is,

`d/(dx)(y)=dy/dx=d/(dx)(3-7x^3+3x^7).`
`:.dy/dx=0-7*3*x^(3-1)+3*7*x^(7-1).`
`:.dy/dx=-21x^2+21x^6.`

Therefore, differentiating `y` w.r.t `x`, comes to be `-21x^2+21x^6.` (answer).