How do you differentiate # F(x) = 3x^2 + 12#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alexander Jul 8, 2016 Using the power rule on #F(x) = 3x^2+12#, which states that #d/dx[x^n] = n*x^(n-1)#, you get #F'(x) = 6x#. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1079 views around the world You can reuse this answer Creative Commons License