How do you differentiate # f(x) =arcsec(2x + 1) #? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Trevor Ryan. Jan 30, 2016 #f'(x)=2/((2x+1)sqrt((2x+1)^2-1)# Explanation: Use the rule : #d/dxsec^(-1)u(x)=1/(usqrt(u^2-1))*(du)/dx# #therefore d/dxsec^(-1)(2x+1)=2/((2x+1)sqrt((2x+1)^2-1)# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 5140 views around the world You can reuse this answer Creative Commons License