# How do you differentiate f(x)=ln(sine^(x^2)) using the chain rule?

$\frac{d}{\mathrm{dx}} \ln \left(\sin {e}^{{x}^{2}}\right) = \frac{1}{\sin {e}^{{x}^{2}}} \cdot \cos {e}^{{x}^{2}} \cdot {e}^{{x}^{2}} \cdot 2 x$
$\frac{d}{\mathrm{dx}} \ln \left(\sin {e}^{{x}^{2}}\right) = \frac{1}{\sin {e}^{{x}^{2}}} \cdot \cos {e}^{{x}^{2}} \cdot {e}^{{x}^{2}} \cdot 2 x$