Question

How do you differentiate `f(x)=ln(sine^(x^2))` using the chain rule?

Answer 1

`d/dxln(sine^(x^2))=1/(sine^(x^2))*cose^(x^2)*e^(x^2)*2x`

Explanation:

Using the chain rule repeatedly, together with other standard rules of differentiation, we get that

`d/dxln(sine^(x^2))=1/(sine^(x^2))*cose^(x^2)*e^(x^2)*2x`