How do you differentiate #f(x)=sin2x^3#?
1 Answer
Apr 13, 2017
Explanation:
differentiate using the
#color(blue)"chain rule"#
#"Given " f(x)=g(h(x))" then"#
#• f'(x)=g'(h(x))xxh'(x)larr" chain rule"#
#rArrf'(x)=cos2x^3xxd/dx(2x^3)#
#color(white)(rArrf'(x))=6x^2cos2x^3#
