# How do you differentiate (sinx^2)/(tanx)?

$\frac{2 x \cos {x}^{2} \tan x - \sin {x}^{2} {\sec}^{2} x}{\tan} ^ 2 x$
$\frac{2 x \cos {x}^{2} \tan x - \sin {x}^{2} {\sec}^{2} x}{\tan} ^ 2 x$