Question

How do you differentiate the following parametric equation: `x(t)=1-lnt, y(t)= cost-t^2`?

Answer 1

`dx/dt = -1/t` and `dy/dt = -sin t -2t`

Explanation:

`dx/dt = -1/t` and `dy/dt = -sin t -2t`. If required to have `dy/dx` , it

would be `dy/dt/dx/dt`

= t(sin t +2t)