# How do you differentiate the following parametric equation:  x(t)=1-lnt, y(t)= cost-t^2 ?

$\frac{\mathrm{dx}}{\mathrm{dt}} = - \frac{1}{t}$ and $\frac{\mathrm{dy}}{\mathrm{dt}} = - \sin t - 2 t$
$\frac{\mathrm{dx}}{\mathrm{dt}} = - \frac{1}{t}$ and $\frac{\mathrm{dy}}{\mathrm{dt}} = - \sin t - 2 t$. If required to have $\frac{\mathrm{dy}}{\mathrm{dx}}$ , it
would be $\frac{\mathrm{dy}}{\mathrm{dt}} / \frac{\mathrm{dx}}{\mathrm{dt}}$