Question

How do you differentiate the following parametric equation: `x(t)=-3e^t-2t, y(t)= -5t^2+2`?

Answer 1

`dy/dx=(10t)/(3e^t+2)`

Explanation:

`x'(t)=-3e^t-2`
`y'(t)=-10t`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(-10t)/(-3e^t-2)=(10t)/(3e^t+2)`