Question

How do you differentiate the following parametric equation: `x(t)=-3t/(1-t), y(t)= 1-tcost`?

Answer 1

`-3/((1-t)^2(tsin(t)-cos(t))`

Explanation:

We have
`dy/dx=(dy/dt)/(dx/dt)=(-3*((1-t-t*(-1))/(1-t)^2)/(-cos(t)+t*sin(t)))`
This is equal to
`-3/((1-t)^2(t*sin(t)-cos(t))`