# How do you differentiate the following parametric equation:  x(t)=3t-1, y(t)= t^2-t+4?

Dec 30, 2015

$\frac{2 t - 1}{3}$

#### Explanation:

$x ' \left(t\right) = 3$
$y ' \left(t\right) = 2 t - 1$

The derivative of the parametric equation is

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{y ' \left(t\right)}{x ' \left(t\right)} = \frac{2 t - 1}{3}$