Question

How do you differentiate the following parametric equation: `x(t)=3t-1, y(t)= t^2-t+4`?

Answer 1

`(2t-1)/3`

Explanation:

`x'(t)=3`
`y'(t)=2t-1`

The derivative of the parametric equation is

`dy/dx=(y'(t))/(x'(t))=(2t-1)/3`