Question

How do you differentiate the following parametric equation: `x(t)=e^(t^2-t) , y(t)=lnt`?

Answer 1

The answer `dx/dt=(2t-1)*e^(t^2-t)`

`dy/dt=1/t`

Explanation:

`x(t)=e^(t^2-t)`

`dx/dt=(2t-1)*e^(t^2-t)`

`y(t)=lnt`

`dy/dt=1/t`