Question

How do you differentiate the following parametric equation: `x(t)=t^2-te^t , y(t)=e^(3t)`?

Answer 1

`dy/dx=(3e^(3t))/(2t-e^t-te^t)`

Explanation:

`x'(t)=2t-e^t-te^t`
`y'(t)=3e^(3t)`

The derivative of the parametric equation is

`dy/dx=(y'(t))/(x'(t))=(3e^(3t))/(2t-e^t-te^t)`