# How do you differentiate the following parametric equation:  x(t)=t-5, y(t)= t^2?

$2 t$
$\frac{\mathrm{dx}}{\mathrm{dt}} = 1 \implies \frac{\mathrm{dt}}{\mathrm{dx}} = 1$
$\frac{\mathrm{dy}}{\mathrm{dt}} = 2 t$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{\mathrm{dy}}{\mathrm{dt}} \times \frac{\mathrm{dt}}{\mathrm{dx}} = 2 t \times 1 = 2 t$