How do you differentiate the following parametric equation: # x(t)=t/(t-4), y(t)=1+t #? Calculus Parametric Functions Derivative of Parametric Functions 1 Answer moutar Jan 10, 2016 #dy/dx = dy/dt * dt/dx# #dy/dx = dy/dt / dx/dt# #dx/dt = (t-4 - t)/(t-4)^2 = -4/(t-4)^2 # #dy/dt=1# #dy/dx = 1/(-4/(t-4)^2) = -(t-4)^2/4# Answer link Related questions How do you find the second derivative of a parametric function? How do you find derivatives of parametric functions? How do you find #dy/dx# for the curve #x=t*sin(t)#, #y=t^2+2# ? How do you find the equation of the tangent to the curve #x=t^4+1#, #y=t^3+t# at the point... How do you find #(d^2y)/(dx^2)# for the curve #x=4+t^2#, #y=t^2+t^3# ? How do you find parametric equations of a tangent line? How do you find parametric equations for the tangent line to the curve with the given parametric... How do you find the equation of a line tangent to the curve at point #t=-1# given the parametric... How do you differentiate the following parametric equation: # x(t)=t^3-5t, y(t)=(t-3) #? How do you differentiate the following parametric equation: # x(t)=lnt, y(t)=(t-3) #? See all questions in Derivative of Parametric Functions Impact of this question 1489 views around the world You can reuse this answer Creative Commons License