Question

How do you differentiate the following parametric equation: `x(t)=t, y(t)= 1-tcost`?

Answer 1

`dy/dx=tsint-cost`

Explanation:

`x'(t)=1`
`y'(t)=-cost+tsint`

The derivative of the parametric function is

`dy/dx=(y'(t))/(x'(t))=(-cost+tsint)/1=tsint-cost`