How do you differentiate #u=root5(t)+4sqrt(t^5)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Monzur R. Dec 24, 2016 #(du)/(dt)=1/(5t^(4/5))+2/sqrt(t^5)# Explanation: #u=t^(1/5)+4(t^5)^(1/2)# If #y=ax^n# then the derivative, #dy/dx=nax^(n-1)# Using this, #(du)/(dt)=1/5t^(-4/5)+4(1/2)(t^5)^(-1/2)=1/(5t^(4/5))+2/sqrt(t^5)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 2629 views around the world You can reuse this answer Creative Commons License