Question

How do you differentiate `x^5+2x^4.3+1/4x^(1/3)`?

Answer 1

Differentiating `x^5+2x^4.3+1/4x^(1/3)` comes to be `5x^4+8.6x^3.3+1/12x^(-2/3).`

Explanation:

Let, `y=x^5+2x^4.3+1/4x^(1/3)=f(x).`

`:.`Differentiating `y` with respect to `x`,

`d/(dx)(y)=dy/dx`.
`:.dy/dx=d/(dx)(x^5+2x^4.3+1/4x^(1/3)).`
`:.dy/dx=5*x^(5-1)+2*4.3*x^(4.3-1)+1/4*1/3*x^(1/3-1).`
`:.dy/dx=5x^4+8.6x^3.3+1/12x^(-2/3).` (answer).