Question

How do you differentiate `y=e^((lnx))^2`?

Answer 1

`y' = 2x`

Explanation:

"e" and the natural logarithms are inverses, so they equal `x` when in the form `ln(e^x)` or `e^(lnx)`.

Thus, `y = x^2`

The derivative of this is obtained using the power rule.

`y'= 2x`

Hopefully this helps!