# How do you differentiate y=e^((lnx))^2?

Dec 21, 2016

$y ' = 2 x$

#### Explanation:

"e" and the natural logarithms are inverses, so they equal $x$ when in the form $\ln \left({e}^{x}\right)$ or ${e}^{\ln x}$.

Thus, $y = {x}^{2}$

The derivative of this is obtained using the power rule.

$y ' = 2 x$

Hopefully this helps!