How do you differentiate #y=e^(x^5+3)#?

1 Answer
May 7, 2017

The derivative of #e^x# is itself, #e^x#. So, when we have a function embedded inside #e^x#, like how here #x# is replaced by #x^5+3#, the derivative of #e^f(x)# where #f# is any other function is given by #e^f(x)*f'(x)#. We multiply by the derivative of #f# due to the chain rule.

In other words:

#d/dxe^x=e^x#

#d/dxe^u=e^u(du)/dx#

Regardless, we see that

#y=e^(x^5+3)#

#dy/dx=e^(x^5+3)d/dx(x^5+3)#

#=5x^4e^(x^5+3)#