Question

How do you differentiate `y=ln(-x)`?

Answer 1

`d/(dx) (ln(-x)) = 1/x`

Explanation:

Using the chain rule with `y= -x`:

`d/(dx) (ln(-x))= ((d(ln(-x)))/(d(-x)))( (d(-x))/(dx)) = (1/(-x))(-1) = 1/x`