How do you divide #(15x^2 + 22x + 8)/( 5x + 4)#?
1 Answer
There is a slight problem with this. Look at the footnote in the explanation.
Explanation:
Method 1: See if you can factorise the numerator such that it cancels out part of the denominator
Method 2: Long division.
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Factors of 15 -> {1,15} ; {3,5}
Factors of 8 -> {1,8} ; {2,4}
Attempt No 1: For this to work we need
Using our list of factors this would give us:
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This works so we have:
But
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However, you have to be mindful of the fact that division by 0 is 'not allowed' in mathematics (Undefined). Thus there is a value of x where
