# How do you divide {(17mn^3)/(m^2+2m-35)}/{(34m^8n^4)/(m^2+7m)}?

$\frac{1}{\left(2 {m}^{6} n\right) \left(m - 5\right)}$
The expression = $\left(\frac{17}{34}\right) \left(\frac{m {n}^{3}}{{m}^{8} {n}^{4}}\right) \left(\frac{{m}^{2} + 7 m}{{m}^{2} + 2 m - 35}\right) = \left(\frac{1}{2}\right) \left(\frac{1}{{m}^{7} n}\right) \left(\frac{m \left(m + 7\right)}{\left(m + 7\right) \left(m - 5\right)}\right)$