Question

How do you divide `{(17mn^3)/(m^2+2m-35)}/{(34m^8n^4)/(m^2+7m)}`?

Answer 1

`1/((2m^6n)(m-5))`

Explanation:

The expression = `(17/34)((mn^3)/(m^8n^4))((m^2+7m)/(m^2+2m-35)) = (1/2)(1/(m^7n))((m(m+7))/((m+7)(m-5)))`
The answer follows.