How do you divide #(25x^2-30x+12) div (5x-3)#?

2 Answers
Aug 1, 2017

#=5x-3#

#=21#

Explanation:

Give -

#(25x^2-30x+12) -:(5x-3)#

enter image source here #

#=5x-3#

#=21#

Aug 1, 2017

#5x-3+3/(5x-3)#

Explanation:

#"one way is to use the divisor as a factor in the numerator"#

#"consider the numerator"#

#color(red)(5x)(5x-3)color(magenta)(+15x)-30x+12#

#=color(red)(5x)(5x-3)color(red)(-3)(5x-3)color(magenta)(-9)+12#

#=color(red)(5x)(5x-3)color(red)(-3)(5x-3)+3#

#"quotient "=color(red)(5x-3)," remainder "=3#

#rArr(25x^2-30x+12)/(5x-3)=5x-3+3/(5x-3)#