How do you divide #(2x^2-6x+6)/(2x - 3)#?

1 Answer
Tony B
Jun 22, 2016

#x-3-3/(2x-3)#

Explanation:

#(2x^2-6x+6)-:(2x-3)#

color(magenta)(
color(white)(
#" "2x^2-6x+6#
#color(magenta)(x)(2x-3) ->" "ul(2x^2-3x" ")larr" Subtract"#
#" "0color(white)(.)-6x+6#
#color(magenta)(-3)(2x-3)->" "ul(-6x+9)larr" Subtract"#
#" "0color(white)(.)color(magenta)(-3)larr" Remainder"#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(magenta)(x-3-) (color(magenta)(3))/(2x-3)#

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