How do you divide #(2x^2 -7x+ 19) div(2x- 3)#?

1 Answer
Oct 27, 2016

"How do you" type questions are answered by explanation.

Explanation:

I use long division:

I am going to use the square root symbol, because I do not find a long division symbol in formatter but please read it as division:

#color(white)_color(white)_color(white)_color(white)_x - 2#
#2x - 3sqrt(2x^2 - 7x + 19) #
#color(white)_color(white)--2x^2 + 3x#
#color(white)_color(white)_color(white).color(white)_0 - 4x + 19#
#color(white)_color(white)_color(white)_color(white)_color(white)_4x - 6#
#color(white)_color(white)_color(white)_color(white)_color(white)_0 + 13#

The quotient is #x - 2# with remainder 13

Written as a mixed number:

#x - 2 + 13/(2x - 3)#