# How do you divide (2x^2 + x – 16) /(x – 3)?

$\frac{2 {x}^{2} + x - 16}{x - 3} = 2 x + 7 + \frac{5}{x - 3}$
$\frac{2 {x}^{2} + x - 16}{x - 3} = 2 x + 7 + \frac{5}{x - 3}$