# How do you divide (-2x^3-2x^2+43x+32)/(x-5) ?

$\left(- 2 {x}^{2} - 12 x - 17\right) - \frac{53}{x - 5}$
Divide $x - 5$ into the first term, giving $- 2 {x}^{2}$. Multiply $x - 5$ $- 2 {x}^{2}$ and subtract this from the original numerator. Repeat this process until there is an indivisible remainder.
Thus the answer is $\left(- 2 {x}^{2} - 12 x - 17\right) - \frac{53}{x - 5}$