How do you divide #(-2x^3-2x^2+43x+32)/(x-5) #? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Roella W. Jan 19, 2016 #(-2x^2 -12x - 17) -53/(x-5)# Explanation: Divide #x-5# into the first term, giving #-2x^2#. Multiply #x-5# #-2x^2# and subtract this from the original numerator. Repeat this process until there is an indivisible remainder. Thus the answer is #(-2x^2 -12x - 17) -53/(x-5)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1443 views around the world You can reuse this answer Creative Commons License