How do you divide $(2 x^{3} + 4 x^{2} - 10 x - 9) \div (x - 3)$ $(2x^3+4x^2-10x-9)÷(x-3)$ ?

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Answer 1 · 2015-10-15T12:36:55

I found:
$(2 x^{3} + 4 x^{2} - 10 x - 9) \div (x - 3) = 2 x^{2} + 10 x + 20$ $(2x^3+4x^2-10x-9)-:(x-3)=2x^2+10x+20$ with a remainder of $51$ $51$ .

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How do you divide (2x3+4x2−10x−9)÷(x−3)(2x^3+4x^2-10x-9)÷(x-3)?