# How do you divide (2x^3+4x^2-10x-9)÷(x-3)?

$\left(2 {x}^{3} + 4 {x}^{2} - 10 x - 9\right) \div \left(x - 3\right) = 2 {x}^{2} + 10 x + 20$ with a remainder of $51$.