How do you divide #(2x^3+4x^2-10x-9)÷(x-3)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Gió Oct 15, 2015 I found: #(2x^3+4x^2-10x-9)-:(x-3)=2x^2+10x+20# with a remainder of #51#. Explanation: Have a look: Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 3359 views around the world You can reuse this answer Creative Commons License