How do you divide #(2x^3-4x^2+16x-8) / (x-2)#?
1 Answer
Apr 8, 2018
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(2x^2)(x-2)cancel(color(magenta)(+4x^2))cancel(-4x^2)+16x-8#
#=color(red)(2x^2)(x-2)color(red)(+16)(x-2)color(magenta)(+32)-8#
#=color(red)(2x^2)(x-2)color(red)(+16)(x-2)+24#
#"quotient "=color(red)(2x^2+16)," remainder "=24#
#rArr(2x^3-4x^2+16x-8)/(x-2)=2x^2+16x+24/(x-2)#
