How do you divide $(2x^3-x^2+7x+15)/(2x-5)$ ?

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Answer 1 · 2017-09-13T00:06:53

$x^2-2x+8.5$ , with a remainder of $27.5$

Using polynomial long division:

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How do you divide (2x^3-x^2+7x+15)/(2x-5) (2x^3-x^2+7x+15)/(2x-5) ?