Question

How do you divide `(3x^2 y^7 z^3) /(4x^3 y^-2 z)`?

Answer 1

`(3x^2y^7z^3)/(4x^3y^(-2)z) = (3y^9z^2)/(4x)`

Explanation:

`(3x^2y^7z^3)/(4x^3y^(-2)z)`

`color(white)("XXXX")` `= (3/4) * ((x^2)/(x^3)) * ((y^7)/(y^(-2))) * (z^3/z)`

`color(white)("XXXX")` `=(3/4) * (1/x) * (y^9/1) * (z^2/1)`

`color(white)("XXXX")` `= (3y^9z^2)/(4x)`