How do you divide $(-3x^3-23x^2-4x+1)/(x-4)$ ?

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Answer 1 · 2018-06-26T05:59:22

$color(green)(=>"Quotient " -3x^2 - 35x - 144, " Remainder " -575/ (x-4)$

$(3x^3 - 23x^2 - 4x + 1 ) / (x - 4)$

$color(white)(aaa) - - - - - - - - - - - - -$

$4 color(white)(aa) | color(white)(aa) -3 color(white)(aaa) -23 color(white)(aaaa) -4 color(white)(aaaa) + 1$

$color(white)(aaa) | color(white)(aaaa) darr color(white)(aa) -12 color(white)(aa)-140 color(white)(aa) -576$

$color(white)(aaa)|- - - - - - - - - - - - -$

$color(white)(aaa)| color(white)(aa) -3 color(white)(aaa) -35 color(white)(aa) -144 color(white)(aa) -575$

$color(green)(=>"Quotient " -3x^2 - 35x - 144, " Remainder " -575/ (x-4)$

How do you divide (-3x^3-23x^2-4x+1)/(x-4) (-3x^3-23x^2-4x+1)/(x-4) ?