How do you divide #( -3x^3+ 3x^2-30x-72 )/(x + 1 )#?

1 Answer
Jan 12, 2016

The fastest method is probably synthetic division; giving:
#(-3x^2+6x-36) -36/(x+1)#

Explanation:

#(color(blue)(-3)x^3,color(blue)(+3)x^2,color(blue)(-30)x,color(blue)(-72)) div (xcolor(red)(+)color(green)(1))#

#{: (,,color(blue)(-3),color(blue)(+3),color(blue)(-30),color(blue)(-72)), (,,,+3,-6,+36), (xx (color(red)(-)color(green)(1)),"|",bar(color(cyan)(-3)),bar(color(cyan)(+6)),bar(color(cyan)(-36)),bar(color(brown)(-36))) :}#

#color(cyan)(-3)x^2color(cyan)(+6)xcolor(cyan)(-36)# with a remainder of #(color(brown)(-36))#