How do you divide #(3x^3-6x^2+13x-4)/(x-3) #?

1 Answer
Tony B
Jul 28, 2016

#3x^2+3x+22+62/(x-3)#

Explanation:

color(white)(.)
#" "3x^3-6x^2+13x-4#
#" "color(magenta)(3x^2)(x-3) ->" "ul(3x^3-9x^2)" "larr" Subtract"#
#" "0color(white)(.)+3x^2+13x-4#
#" "color(magenta)(3x)(x-3)->" "ul(3x^2-9x) larr" Subtract"#
#" "0+22x-4#
#" "color(magenta)(22)(x-3) ->" "ul(22x-66) larr" Subtract"#
#" "0color(magenta)(+62 larr" Remainder")#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#3x^2+3x+22+62/(x-3)#

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