How do you divide $\frac{3 x^{4} + 22 x^{3} - 2 x^{2} + 2 x - 7}{x - 2}$ $(3x^4+22x^3-2x^2+2x-7)/(x-2)$ ?

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How do you divide $\frac{3 x^{4} + 22 x^{3} - 2 x^{2} + 2 x - 7}{x - 2}$ $(3x^4+22x^3-2x^2+2x-7)/(x-2)$ ?

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Answer 1 · 2017-05-28T16:28:53

$3 x^{3} + 28 x^{2} + 54 x + 110$ $color(blue)(3x^3+28x^2+54x+110$ and remainder of $213$ $color(blue) 213$

Explanation:

$color(white)(.............)3x^3+28x^2+54x+110$
$color(white)(aa)x-2$ $|$ $overline(3x^4+22x^3-2x^2+2x-7)$

$color(white)(..............)ul(3x^4-6x^3)$
$color(white)(........................)28x^3-2x^2$
$color(white)(........................)ul(28x^3-56x^2)$
$color(white)(...................................)54x^2+2x$
$color(white)(....................................)ul(54x^2-108x)$
$color(white)(...............................................)110x-7$
$color(white)(...............................................)ul(110x-220)$
$color(white)(............................................................)213$

$color(blue)(3x^3+28x^2+54x+110$ and remainder of $color(blue) 213$

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How do you divide $\frac{3 x^{4} + 22 x^{3} - 2 x^{2} + 2 x - 7}{x - 2}$ $(3x^4+22x^3-2x^2+2x-7)/(x-2)$ ?

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How do you divide (3x^4+22x^3-2x^2+2x-7)/(x-2) 3x4+22x3−2x2+2x−7x−2(3x^4+22x^3-2x^2+2x-7)/(x-2) ?

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How do you divide $\frac{3 x^{4} + 22 x^{3} - 2 x^{2} + 2 x - 7}{x - 2}$ $(3x^4+22x^3-2x^2+2x-7)/(x-2)$ ?