How do you divide #(4x^3+7x^2-9x+15)/(x+1) #?

1 Answer
Tony B
Jun 14, 2017

#4x^2+3x-12+27/(x+1) #

Explanation:

#" "4x^3+7x^2-9x+15#
#color(magenta)(+4x^2)(x+1)-> ul(4x^3+4x^2" "larr" Subtract")#
#" "0 color(white)(x^3) +3x^2-9x+15#
#color(magenta)(+3x)(x+1)->" " ul(3x^2+3x" "larr" Subtract")#
#" "0color(white)(x^2)-12x+15#
#color(magenta)(-12)(x+1)->" "ul(-12x-12" "larr" Subtract")#
#" "0color(white)(x)color(magenta)(+27 larr" Remainder")#

#color(magenta)( 4x^2+3x-12+27/(x+1) )#

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