How do you divide $\frac{5 x^{2} + 22 x + 8}{6 x + 8}$ $(5x^2 + 22x + 8)/( 6x+8)$ ?

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How do you divide $\frac{5 x^{2} + 22 x + 8}{6 x + 8}$ $(5x^2 + 22x + 8)/( 6x+8)$ ?

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Answer 1 · 2017-02-10T21:47:36

$\frac{5}{6} x + \frac{23}{9} - \frac{112}{54 x + 72}$ $5/6x+23/9 - 112/(54x+72)$

Explanation:

I am afraid you are into fractions with this one!

$5 x^{2} + 22 x + 8$ $" "5x^2+22x+8$
$5/6x(6x+8) ->" "ul(5x^2+40/6x) larr" subtract"$
$" "0+46/3x+8$
$46/(3xx6)(6x+8)->" " ul(46/3x+184/9) larr" subtract"$
$" "0 -112/9$
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$(5x^2+22x+8)/(6x+8)" "=" "5/6x+23/9 - 112/(9(6x+8))$

$" "=5/6x+23/9 - 112/(54x+72)$

$color(red)("That was cruel!!!!")$

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How do you divide $\frac{5 x^{2} + 22 x + 8}{6 x + 8}$ $(5x^2 + 22x + 8)/( 6x+8)$ ?

1 Answer

Explanation:

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How do you divide $\frac{5 x^{2} + 22 x + 8}{6 x + 8}$ $(5x^2 + 22x + 8)/( 6x+8)$ ?