How do you divide #(5x-5)/16div(x-1)/6#?

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Answer 1 · 2015-06-03T04:22:41

Dividing by #a/b# is the same as multiplying by #b/a#

Thus :

#=(6*(5x-5))/(16*(x-1))#

#=(6*5*(x-1))/(16*(x-1))# ( because #5*(x-1)=5x-5# )

#=(30*(x-1))/(16*(x-1))#

#=30/16# ( we divide by #x-1# on each side )

# = 15/8# ( we symplify by dividing by 2 both numerator and denominator )